Question

the difference between the two digit number is 4 and the ratio between the number in the 10th place and and the number in the until place is 1:3 what is the sum of digit of that number

Answer 1

$\bold{\texit{\huge{ANSWER}}}$

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$\underline{\large{\bold{GIVEN}}}$

● Difference between the two digits of a number = 4

● Ratio = 1 : 3

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$\underline{\large{\bold{SOLUTION}}}$

Let the tens place digit be x

Let the unit place digit be 3x

Therefore , we get that unit place digit is greater than the tens place digit

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$\underline{\large{\bold{THE \: EQUATION \: FORMED}}}$

3x - x = 4

=> 2x = 4

=> x = 4/2

=> x = 2

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Tens place digit = 2

Unit place digit = 3 × 2 = 6

The number obtained = 26

Sum of the digits = 2 + 6 = 8 ANS

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#BE BRAINLY

@Sanskriti141

Answer 2

Here is your solution

GIVEN​ :-

Difference between the two digits of a number = 4

Given Ratio = 1 : 3

​ 
Let,
The tens place digit be x 

Let,
The unit place digit be 3x

Now Our assumption

unit place digit is greater than the tens place digit.

New equation

a/q

=>3x - x = 4

=> 2x = 4

$=>x = \frac{\cancel4}{\cancel2}\:{}2$

=> x = 2

we get

Tens place digit = 2

Unit place digit = 3 × 2 = 6

The number obtained = 10x+6=10×2+6=26

Sum of the digits = 2 + 6 = 8