Question

The difference between the two molar specific heats at a gas is 8000 j kg k. If the ratio of the two specific heats is 1.65; calculate the two molar specific heats

Answer 1

Answer:

Correct option is

D

10375 J/kg−K

We know that,

C

p

−C

V

=nR

C

p

/C

V

=1.4

C

p

−C

V

=4150

0.4C

V

=4150

C

V

=4150/0.4

C

V

=10375

Hence option(D)