Question

The difference between the two numbers 6 and their squares is 252 the sum of those numbers

Answer 1

It's pretty simple , Let two numbers be x and y,

According to the question,

x - y = 6, and x²-y² = 252,

We know that a²-b² = (a+b)(a-b), Using this formula we can get the answer,

=> (x+y) (x-y) = 252,
=> (x+y) = 252/6 = 126/3 = 42

=> x + y = 42, Which is the sum of two numbers,

So the sum of two numbers whose difference is 6 is 42,

Hope you understand, Have a great day !!

Answer 2

Let one no. be x
and the another no. be y

ATQ,

$x - y = 6 \: \: ....(i) \\ \\ {x}^{2} - {y}^{2} = 252 \\ = > (x - y)(x + y) = 252 \\ = > 6(x + y) = 252 \: \: \: \: \: \: .....from(i) \\ = > (x + y) = \frac{252}{6} \\ x + y = 42$

Hence, 44 will be the sum of both numbers.

Hope you understood it.

Please mark it as the brainliest.