The difference between the two numbers
is 7. Two times the smaller number added
to the larger number gives 22. Find the
two
numbers. 5.3 tables and 2 chairs cost
Rs.1900 and 2 tables and 4 chairs cost R.
1800. Find the cost of table and a chair
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Answer:
The numbers are 5 and 12
Difference between the two no is 7.
So let one no be x. Then
other no = x + 7.
Now,
Two times the smaller no = 2x
Two times the smaller no added to larger no = 22
2x + x + 7 = 22
3x + 7 = 22
3x = 15
x = 5.
Smaller no = 5
Larger no = x + 7 = 5 + 7 = 12
next question :
let table cost be x
let chair cost be y
A/q
3x+2y=1900.....1
2x+4y=1800......2
multiply on both sides in Eq.1 by 2
now, 6x+4y = 3800....3
2x+4y=1800......4
on solving Eq.3 and 4
4x = 2000
x=500
3×500+2y = 1900
y =400
thus, cost of table is Rs. 500 and chair cost is Rs. 400
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