The difference between the two specific heats of gas is 1600 and their ratio is 6:1 find cp & Cv
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Given,
The difference between the two specific heats of gas, R = 1600
The ratio between , r= 6:1 = 1.6
To Find,
Solution,
= 4.266 ×10³ J/mole-°c
= = 2.66 × 10³J/mole-°c
∴Hence, is 4.266 ×10³ J/mole-°c and is 2.66 × 10³J/mole-°c.
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