The difference between two acute angle of a right angle triangle is 36. Find these angle in radians and degrees
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Answered by
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let the 2 acute angles be x and y
goven x- y= 36
then x = 36 + y
now the given triamgle is and right angled triangle so one angle will be 90°
we know that sum of all angles of a triangle is 180°
so, y + 36 + y + 90 = 180
2y = 180 - 90 - 36
2y = 54°
y = 27°
now x will be 36 + 27 = 63°
1° = π / 180° so,
y = (27) x π / 180
= 0.147 rad.
or
3π / 20 rad
x = (63) x π / 180
x = 1.099 rad.
or
= 7π / 20 rad.
goven x- y= 36
then x = 36 + y
now the given triamgle is and right angled triangle so one angle will be 90°
we know that sum of all angles of a triangle is 180°
so, y + 36 + y + 90 = 180
2y = 180 - 90 - 36
2y = 54°
y = 27°
now x will be 36 + 27 = 63°
1° = π / 180° so,
y = (27) x π / 180
= 0.147 rad.
or
3π / 20 rad
x = (63) x π / 180
x = 1.099 rad.
or
= 7π / 20 rad.
Answered by
0
Answer:
let the 2 acute angles be x and y
goven x- y= 36
then x = 36 + y
now the given triamgle is and right angled triangle so one angle will be 90°
we know that sum of all angles of a triangle is 180°
so, y + 36 + y + 90 = 180
2y = 180 - 90 - 36
2y = 54°
y = 27°
now x will be 36 + 27 = 63°
1° = π / 180° so,
y = (27) x π / 180
= 0.147 rad.
or
3π / 20 rad
x = (63) x π / 180
x = 1.099 rad.
or
= 7π / 20 rad.
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