Question

the difference between two acute angles of a right angled triangle π/9 radians. find the angles in degree

Answer 1

solution;

${1}^{c} = ( \frac{180}{\pi})degree$

Now,
${ \frac{\pi}{9} }^{c} = { \frac{180}{\pi} } \times \frac{\pi}{9}$
= 20°

Let, two acute angles be x and y

so,
ATQ, X - y= 20°......(1)

x+ y= 90°......(2)

solving 1 & 2, we get;

=>2x= 110°

=> x= 55°

putting the value of x in 2, we get;

=> 55°+ y= 90°

=> y= 35°

so, Two acute angles are 55° & 35°

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Hope you get it...

#Amrit⭐

Answer 2

Step-by-step explanation:

hope the attachment helps you.......