Question

the difference between two integer is two the larger integer is 6 less than twice the smaller find the integers
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Answer 1

To Find:-

• Find the integers.

Given:-

• Difference between two integer is two the larger integer is 6 less than twice the smaller.

Solution:-

Let the smaller number be ' x '

And the larger number be 2x - 6

Then,

The equation is

➣ 2x - 6 - x = 2

➣ x = 6 + 2

➣ $\boxed{\bf{\color{yellw}{ \: x \: = \: 8 \: }}}$

So,

The larger number is

➣ 2x - 6

➣ 2( 8 ) - 6

➣ 16 - 6

➣ 10

$\boxed{\bf{\color{yellw}{ \: ∴ \: The \: larger \: number \: is \: 10 \: and \: smaller \: number \: is \: 8. \: }}}$

Verification:-

Given,

2x - 6 is the largest number.

➣ 2x - 6 = 10

➣ 2( 8 ) - 6 = 10

➣ 16 - 6 = 10

➣ 10 = 10

Answer 2

Answer :-

Let the number be x and y and let x be greater integer and y be smaller integer.

According to the question :-

Difference between x and y is 2

So, x - y = 2

→ x = y + 2 - i

Larger integer is 6 less than twice the smaller :-

→ x = 2y - 6 - ii

Equating the equation i and ii -

→ y + 2 = 2y - 6

→ 2y - y = 6 + 2

→ y = 8

→ x = y + 2

→ x = 8 + 2

→ x = 10

Numbers = 8,10