Question

The difference between two natural numbers is 4 and their product is 221. find the numbers.​

Answer 1

Answer:

let the two numbers be Xand Y

A/Q-

X - Y = 4

and

XY = 221

Y(4+Y)= 221

Y^2 + 4Y -221= 0

Y^2 +17Y - 13Y - 221 = 0

Y(Y + 17) - 13(Y + 17)=0

(Y-13)(Y+17)=0

Y-13=0 or Y+17= 0

Since Y is natural number so , Y = 13

then X= 17

hence the two natural numbers are 13and17

Answer 2

Answer:

y+4 = x is one number and x is another number

x-y= 4

xy=221

x=221/y

221/y-y=4

221-y^2=4y

y^2+4y-221=0

y^2+17y-13y-221=0

y(y+17)-13(y+17)=0

y-13(y+17)=0

y-13=0

y=13

y+17=0

y=-17

x=221/y

= -221/17. 221/13

=-13 & 17

sice they are natural numbers , they should be positive

hence if x = 13 , y =17 and vice versa

Step-by-step explanation:

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