the difference between two number is 40 If the smaller number is divided by the larger number fraction is 6/11 find the number
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Answered by
6
Let the smaller no . be x
And the greater no.be = x+40
x/x+40 = 6/11
11x= 6 (x + 40)
11x = 6x + 240
11x-6x=240
5x = 240
x = 48
So the smaller no= 48, and the greater no = 48 + 40 = 88
And the greater no.be = x+40
x/x+40 = 6/11
11x= 6 (x + 40)
11x = 6x + 240
11x-6x=240
5x = 240
x = 48
So the smaller no= 48, and the greater no = 48 + 40 = 88
Answered by
0
x-y=40 (x is larger)
x=40+y
x/y = 6/11
40+y/y = 6/11
440+11y=6y
5y=440
y=88
x=40+y
x/y = 6/11
40+y/y = 6/11
440+11y=6y
5y=440
y=88
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