Question

The difference between two numbers is 14 their lcm and hcf are 441 and 7

Answer 1

Answer:

Let 1st no=x,2nd no=y,

A/c to qustn,x-y=14

x=14+y

we know,

HCF*LCM=n1*n2

7*441=x*y

3087=(14+y)*y

3087=14y+y^2

y^2+14y-3087=0

y^2+63y-49y-3087=0

y(y+63) -49(y+63)=0

(y-49) (y+63)=0

so,y=49,then x=y+14=49+49=63

Hence,nos are 49 and 63.

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Answer 2

The difference of two numbers is 14.their lcm and hcf are 441 and 7.find the numbers?

Answer:

The required numbers are  63 and 49

Step-by-step explanation:

Concept:

Product of two numbers= (HCF)*(LCM)

Let the two numbers be x and y with x>y.

Also x - y=14...............(1)

H.C.F of x and y =7

L.C.M of x and y= 441

Then,

xy=441*7

xy=7*3*7*3*7

xy=63*49.................(2)

From (1) and (2)

x= 63 and y=49