Question

the difference between two numbers is 26 and one number is three times the other. find them.

Answer 1

Let the two numbers be x & y
A/q
x = 3y ......(i)
x-y = 26 ......(ii)

From (i) , we get
x = 3y
&
From (ii) , we get
x-y = 26
y = x-26
So by substituting the value of x in (ii), we get
y = 3y-26
3y -y = 26
2y = 26
y = 26/2 = 13
So, y = 13
& x = 3y = 3 * 13 = 39

So, x = 39
& y = 13

Ok!
Thanks for asking me this question.

Answer 2

$\bf\huge\boxed{\boxed{\bf\huge\:Hello\:Mate}}}$

$\bf\huge Let \:the\:number\:be\:p\:and\:y$

$\bf\huge => p - y = 26 (Eqn 1)$

$\bf\huge => p = 3y (Eqn 2)$

$\bf\huge From\:Eqn(2) => y = \frac{p}{3}$

$\bf\huge Put\:the\:value\:in\:Eqn(1)$

$\bf\huge => p - \frac{p}{3} = 26$

$\bf\huge => 3p - p = 78$

$\bf\huge => 2p = 78$

$\bf\huge => p = 39$

$\bf\huge Substitute\:p = 39 \:in\:Eqn(2)$

$\bf\huge => 39 = 3y$

$\bf\huge => y = \frac{39}{3} = 13$

$\bf\huge Required\:Number\:=\:39\:and\:13$

$\bf\huge\boxed{\boxed{\:Regards=\:Yash\:Raj}}}$