Question

The difference between two numbers is 26. Bigger number is three times the smaller number find the smaller product

Answer 1

Step-by-step explanation:

• let bigger number be x.
• let smaller number be y.
• given difference between two numbers is 26.
• so x - y = 26

x = y +26 .....equation 1

• also given bigger number is three times the smaller number.
• so x = 3y...... equation 2
• keeping equation 1 in equation 2
• 26+y = 3y
• 26=3y -y
• 26=2y
• 26/2=y
• 13=y
• hence smaller number is 13
• to find bigger number
• x - y =26
• x-13=26
• x=26+13
• x=39
• hence bigger number is 39.

hope this helps you .

Answer 2

$\bf{\underline{\underline \blue{Solution:-}}}$

$\sf\underline{\red{\:\:\: Correct \: Question:-\:\:\:}}$

• The difference between two numbers is 26 and one number is three times the other. Find them.

$\sf\underline{\red{\:\:\: AnswEr:-\:\:\:}}$

• The requireds numbers = 39 and 13

$\sf\underline{\red{\:\:\: Given:-\:\:\:}}$

• The difference between the two numbers is 26.
• One number is three times the other.

$\sf\underline{\red{\:\:\: Need\:To\: Find:-\:\:\:}}$

• The required numbers = ?

$\bf{\underline{\underline \blue{Solution:-}}}$

Let larger number be x.

And smaller number be y.

$\sf\underline{\pink{\:\:\: Now,\:it\: is \: given\:that:-\:\:\:}}$

• The difference between two numbers is 26

$\longrightarrow \sf {x - y = 26............... (1) }$

$\sf\underline{\pink{\:\:\: Also,\:one\: number\:is\:three \:times \:other:-\:\:\:}}$

$\longrightarrow \sf {x = 3y............... (2) }$

$\sf\underline{\pink{\:\:\: Now,\:our\: equations \:are:-\:\:\:}}$

$\longrightarrow \sf {x - y = 26............... (1) }$

$\longrightarrow \sf {x = 3y............... (2) }$

$\sf\underline{\green{\:\:\: Putting\:(2)\: in \:(1):-\:\:\:}}$

$\dashrightarrow \sf {x - y = 26}$

$\dashrightarrow \sf {(3y) - y = 26}$

$\dashrightarrow \sf {2y = 26}$

$\dashrightarrow \sf {y = \dfrac{\cancel{26}}{\cancel{2}} }$

$\dashrightarrow \sf {y = 13}$

$\sf\underline{\green{\:\:\: Putting\: y = 13 \:in \:(2):-\:\:\:}}$

$\dashrightarrow \sf {x = 3y}$

$\dashrightarrow \sf {x = 3 \times 13 }$

$\dashrightarrow \sf {x = 39}$

$\sf\underline{\orange{\:\:\: ThereFore:-\:\:\:}}$

x = 39 and y = 13 is the solution for the above equation.

$\sf\underline{\orange{\:\:\: So:-\:\:\:}}$

$\dashrightarrow \sf {Larger \: Number = x}$

$\dashrightarrow \sf {Larger \: Number = 39}$

$\sf\underline{\pink{\:\:\: And:-\:\:\:}}$

$\dashrightarrow \sf {Smaller \: Number = y}$

$\dashrightarrow \sf {Smaller \: Number = 13}$

$\sf\underline{\pink{\:\:\: Hence:-\:\:\:}}$

• The requireds numbers are 39 and 13.

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