The difference between two numbers is 3 and the difference of their squares is 63. Find the greater number. (a) 12 (b) 9 (c) 15
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Let, the smaller number be x.
then, another number will be 3+x.
Now,
(x+3)² - x² = 63
x²+6x+9-x² = 63
6x = 54
x = 9
Greater number = x+3 = 12.
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then, another number will be 3+x.
Now,
(x+3)² - x² = 63
x²+6x+9-x² = 63
6x = 54
x = 9
Greater number = x+3 = 12.
Mark as brainliest,if it helped, thank you.
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