Question

the difference between two numbers is 3. their product is 40. find the numbers​

Answer 1

Answer:

If a and b are the numbers, a-b=3, so b=a-3, and ab=40, so a(a-3)=40. a^2-3a-40=0 factorises: (a+5)(a-8)=0.

Answer 2

Difference=3

product=40

this means

EQ.1 → x-y=3

EQ.2 → x*y=40

form here try trial and error method:

let's take x=8, y=5

now substitute in both equations

EQ.1 → 8-5=3

EQ.2 → 8*5= 40...