The difference between two numbers is 320. If 12% of one number is 10% of the other. Find the numbers.
Answers
Answered by
1
Answer:
The numbers are 1920 and 1600
Step-by-step explanation:
x - y = 320
10/100x = 12/100y
10x - 12y = 0
10x - 10y = 3200
subtracting the 2 equations
-2y = -3200
y = 1600
x = 1600 + 320
x = 1920
Answered by
1
Answer:
1600 , 1920
Step-by-step explanation:
let a and b be the numbers,
given, b - a = 320 (b is assumed to be greater than a )
=> b = 320+a ------------ (1)
also 12% of a = 10% of b
=> 12% of a = 10% of (320+a)
=> 12a/100 = [10(320+a)] / 100
=> 12a = 3200+10a
=> 12a-10a = 3200
=> 2a = 3200
=> a = 3200/2
=> a = 1600
so , b = 320 + 1600 = 1920
verification:
12% of 1600 = 1600* (12/100) = 16*12 = 192
10% of 1920 = 1920 * (10/100) = 192*1 = 192
equal
hence verified
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