Question

The difference between two numbers is 4.if the sum of five times the smaller number and the bigger number is 58, find the numbers. ​

Answer 1

Answer:

x and y be the two numbers such that x>y.

x−y=4.....(1)

Also,

5y+x=58.....(2)

Subtracting equation (1) from (2), we have

(5y+x)−(x−y)=58−4

6y=54

⇒y=

6

54

=9

∴x−9=4⇒x=9+4=13

Answer 2

Answer:

Step-by-step explanation:

Let the 2 numbers be x and y and let x >y

x - y = 4                ....(1)

5y + x = 58          ....(2)  

We will solve this by substitution method.

x - y = 4 ⇒ x = 4 + y

Lets substitute for x in (2) equation.

5y + (4 + y) = 58

⇒ 6y + 4 = 58

Lets solve for y

⇒ 6y + 4 - 4 = 58 - 4

⇒ 6y = 54

⇒ 6y/6 = 54/6 ⇒ y = 9

Now we know x - y = 4

x - (9) = 4 ⇒ x - 9 + 9 = 4 + 9

⇒ x = 13

∴ x = 13 and y = 9