Question

The difference between two numbers is 72 and the quotient obtained by dividing the one by other is 3. Find the numbers

Answer 1

$\mathfrak{\huge{Answer:}}$

$\mathbb{GIVEN}$

Difference between numbers = 72

Quotient which we get after dividing the two numbers = 3

$\mathbb{TO\:FIND}$

The two numbers which go with the conditions given to us

$\mathbb{METHOD}$

We can let the numbers to be = x and y

Even in this, we'll let x > y

According to the given question:

$\tt{x - y = 72}$ ...(1)

Next equation:

$\tt{\frac{x}{y} = 3}$ ...(2)

We can find the value of x from equation (2) and put it in the equation (1):

From the equation (2):

x = 3y

Put it in equation (1):

x - y = 72

=》 3y - y = 72

=》 2y = 72

=》 y = 36

x = 72 - y = 72 + 36 = 108

Thus, numbers are $\sf{\huge{36\:and\:108}}$

Answer 2

Let nos be x and y

As difference is 72

So

x - y = 72 Assuming x>y

As x>y and quotient obtained is 3

So it should be x/y to make it greater than 1

So x/y = 3

Apply Componendo and dividendo

x+ y)/ x-y) = 3+1)/ (3-1)

x+ y)/ 72 = 4 /2 = 2

x+ y = 72× 2 = 144

And X - Y = 72

Add

2x = 144+72 = 216

x= 108

Y = x-72 = 108-72 = 36

So

Two nos are 108, 36

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