the difference between two numbers is 8 if 2 is added to the bigger number the result will be 3 times the smaller number find the numbers
Answers
Answered by
7
Hey mate..
=======
Let the smaller number be x
And the bigger number be y
Given,
The difference between two numbers is 8
So,
y - x = 8....(1)
Also,
If 2 is added to the bigger number the result will be 3 times the smaller number.
So,
=> 2 + y = 3x
=> 3x - y = 2......(2)
Adding Eq. (2) From Eq.(1) we get,
=> ( y - x ) + ( 3x - y ) = 8 - 2
=> y - x + 3x - y = 6
=> 2x = 6
=> x = 6 / 2
=> x = 3
Putting the value of x = 3 in Eq. (1) we get ,
=> y - 3 = 2
=> y = 2 + 3
=> y = 5
Thus,
The required values of x and y are 3 and 5 respectively.
Hope it helps !!
=======
Let the smaller number be x
And the bigger number be y
Given,
The difference between two numbers is 8
So,
y - x = 8....(1)
Also,
If 2 is added to the bigger number the result will be 3 times the smaller number.
So,
=> 2 + y = 3x
=> 3x - y = 2......(2)
Adding Eq. (2) From Eq.(1) we get,
=> ( y - x ) + ( 3x - y ) = 8 - 2
=> y - x + 3x - y = 6
=> 2x = 6
=> x = 6 / 2
=> x = 3
Putting the value of x = 3 in Eq. (1) we get ,
=> y - 3 = 2
=> y = 2 + 3
=> y = 5
Thus,
The required values of x and y are 3 and 5 respectively.
Hope it helps !!
Answered by
0
Let the numbers be a and b
a-b = 8 ..........(a)
(a+2) - b = 3b
a+2 = 4b
a = 4b-2 ................(b)
Substituting in (a),
4b-2-b = 8
3b = 10
b = 3.5
a - b = 8
a = 11.5
a-b = 8 ..........(a)
(a+2) - b = 3b
a+2 = 4b
a = 4b-2 ................(b)
Substituting in (a),
4b-2-b = 8
3b = 10
b = 3.5
a - b = 8
a = 11.5
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