Math, asked by sanjupawaskar4, 3 months ago

The difference between two numbers is 8. If 2
is added to the greater number, the result will
be three times the smaller. Find the numbers.​

Answers

Answered by Anonymous
52

Answer:

★ Greater number = 13 ★

★ Smaller number = 5 ★

Step-by-step explanation:

Given:

  • The difference between two numbers is 8.
  • If 2 is added to the greater number, the result will be 3 times the smaller.

To find:

  • The two numbers.

Solution:

Let the greater number be x and the smaller number be y.

According to the 1st condition,

  • The difference between two numbers is 8.

\implies x-y=8

\implies x = 8+y................(i)

According to the 2nd condition,

  • If 2 is added to the greater number, the result will be 3 times the smaller.

• If 2 is added to the greater number, the number will be = (x+2)

\implies x+2=3y

  • [ Put x = 8+y from eq(i) ]

\implies 8+y+2=3y

\implies y-3y=-10

\implies -2y=-10

\implies y = 10/2

\implies y = 5

  • Smaller number = 5

Now put y = 5 in eq(i) for getting the value of x.

x = 8+y

→ x = 8+5

→ x = 13

  • Greater number = 13

__________________

Answered by Anonymous
34

\large{\textbf{\underline{ \:  Given:- \:  \: }}}

❏Diff. between two numbers is 8

❏After 2is added to the greater number the new number will be 3times the smaller one.

\large{\textbf{\underline{ \:  Find:- \:  \: }}}

❏What will be the numbers.

\large{\textbf{\underline{ \:  Solution:- \:  \: }}}

Let, the smaller number be x

and the greater number be y

\underline{\textsf{According To Question:-}}

\sf \ast \:  \:  y - x = 8 ...... \bigg\langle  eq....1\bigg\rangle \\

\sf \ast \:  \:  y + 2 = 3x ...... \bigg\langle  eq....2\bigg\rangle \\

Taking Eq. 1

\sf \bullet\implies\:  \:   y - x = 8 \\

\sf \bullet\implies\:  \:   y = 8 + x \\

\underline{\textsf{Using value of y in eq.1:-}}

\sf \dashrightarrow\:  \:  y + 2 = 3x \\

\sf \dashrightarrow\:  \:  8 + x + 2 = 3x \\

\sf \dashrightarrow\:  \:  10+ x= 3x \\

\sf \dashrightarrow\:  \:  10= 3x - x \\

\sf \dashrightarrow\:  \:  10=2x \\

\sf \dashrightarrow\:  \:   \dfrac{10}{2}=x \\

\sf \dashrightarrow\:  \:  5=x \\

 \therefore \underline{\textsf{\small{Smallest number, x = 5}}} \\

\underline{\textsf{Substituting the value of x in eq.1:-}}

\sf \implies\:  \:   y - x = 8 \\

\sf \implies\:  \:   y - 5 = 8 \\

\sf \implies\:  \:   y= 8 + 5\\

\sf \implies\:  \:   y= 13\\

 \therefore \underline{\textsf{\small{Greater number, y = 13}}} \\

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Hence,

  • Smallest No. = 5
  • Greatest No. = 13

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