Question

The difference between two parallel sides of a trapezium is 4 cm. The perpendicular distance between them is 19 cm. If the area of the trapezium is 475 cm, find the lengths of the parallel sides.​

Answer 1

Step-by-step explanation:

Let the two parallel sides of the trapezium be a cm and b cm.

Given that difference between the two parallel sides is 4 and the perpendicular distance(h) is 19

⇒a−b=4⟶(1)

We know that Area of Trapezium =

2

1

×(a+b)×h

Substituting the values of h we get,

2

1

×(a+b)×19=475

⇒(a+b)=

19

475×2

⇒a+b=50⟶(2)

Adding (1) and (2),

a−b=4

a+b=50

−2b=−54

b=

2

54

=27

Putting b=27 in (2) we get

a+27=50

a=50−27=23

Two parallel sides are 27 cm and 23 cm.

Answer 2

Question

The difference between two parallel sides of a trapezium is 4 cm.The perpendicular distance between them is 19 cm.Find the area of the trapezium and find the length of parallel sides.

Solution

Let the two parallel sides of the trapezium be a cm and b cm.

Given that difference between the two parallel sides is 4 and the perpendicular distance(h) is 19

⇒a−b=4⟶(1)

We know that Area of Trapezium = 21×(a+b)×h

Substituting the values of h we get,

21×(a+b)×19=475

⇒(a+b)=19475×2

⇒a+b=50⟶(2)

Adding (1) and (2),

a−b=4

a+b=50

−2b=−54

b=254=27

Putting b=27 in (2) we get

a+27=50

a=50−27=23

Two parallel sides are 27 cm and 23 cm.

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