Question

the difference between two positive integers is 36. the integers are in the ratio 4:3 find the integers​

Answer 1

Answer:

Let those two positive integers be a,b (a<b)

Given that, b-a = 36 ___(1)

and a:b = 4:3 = k

Then, a = 3k, b = 4k

Now substitute the assumed values of a,b in (1)

You get 4k - 3k = 36 → k = 36.

So, a = 3k = 108

& b = 4k = 144

Conclusion:

Those two integers are 108,144

Answer 2

Answer :

• 144 and 180 are the integers

Given :

• The difference between two positive integers is 36
• The integers are in the ratio 4:3

To find :

• Integers

Solution :

• Let the integers be x

Given, the integers are in the ratio 4 : 3 so

• Let the ratio be 4x and 3x

And also Given that the difference between two positive integers is 36 so,

According to question :

➝ 4x - 3x = 36

➝ x = 36

• 4x = 4(36) = 144
• 3x = 3(36) = 108

Hence , 144 and 180 are the integers

Verification :

➝ 4x - 3x = 36

➝ 4(36) - 3(36) = 36

➝ 144 - 108 = 36

➝ 36 = 36

Hence , Verified