Question

the difference between two positive integers is 4 and the sum of their square is 40. find the greater number​

Answer 1

Answer:

2 and 6

Step-by-step explanation:

because 6 square is 36 and 3 square is four

thus 36 + 4 = 40

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Answer 2

Answer:

given

1)a-b=4

a=b+4

2)a^2+b^2=40

(b+4)^2+b^2=40

slove for b

b^2+8b+16+b^2-40=0

2(b^2+4b-12)=0

factoring gives

(b-2)(b-6)=0

since the numbersare positive,we have b=2.

Therfore the two numbers are 2 and 6