The difference between two positive integers is 4. If the sum of their squares is 296, then the
sum of numbers will be
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Answer: Let two positive integers ' a ' and ' b' are such that-
a-b = 4
a^2+b^2 = 296
since (a-b)^2 = a^2 + B^2 -2ab
therefor 2ab = 280
by (a+b)^2 = a^2 + b^2 +2ab
a+b=24 answer
Step-by-step explanation:
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