Question

The difference between two positive numbe
7 and the square of their sum is 289. Find the two numbers.​

Answer 1

Answer:

Let the two number be X and Y

Step-by-step explanation:

X-Y=7

Y=X-7

(X+Y)^2=289

X^2+Y^2+2XY=289

X^2+(X-7)^2+2X (X-7)

X^2+X^2+49-14X+2X^2-14X

4X^2+49-28X

Answer 2

Step-by-step explanation:

Let the two no. are x and y

x-y=7 ----- I

(x+y)^2=289

x+y. =√289

x+y. =17 -------II

x-y =7 ------I

x+y=17 -----II

-------------

2x 0=24

x =24/2

x =12

substitute x=12 in the equation I

x-y =7

12-y=7

-y=7-12

-y=-5

y=5

therefore the two numbers are 12 and 5