Question

 the difference between two positive numbers is 10. Find the numbers, if the square of the greater exceeds twice the square of the smaller by the maximum amount​

Answer 1

Answer:

Let smaller number is x Greater number = 2x + 15 According to the question Greater number+ smaller ... The difference of their square is 2,500. ...

Answer 2

The Numbers are 20 and 10

Step-by-step explanation:

If one number is x then the other number will be x-10

Now, according to the question difference between the square of the greater and twice the square of the smaller number

$x^2-2(x-10)^2$

$=x^2-2(x^2-20x+100)$

$=x^2-2x^2+40x-200$

$=-x^2+40x-200$

$=-200-(x^2-40x+400)+400$

$=200-(x-20)^2$

This value will be maximum when x=20

Thus, the numbers are 20 and 10

Hope this answer is helpful.

Know More:

Q: The difference between two positive numbers is 7 and the square of their sum is 289. find the two numbers.

Click Here: https://brainly.in/question/6744296

Q: The difference between two positive numbers is 10 and the ratio between them is 5:3. Find the product of the two numbers.

Click Here: https://brainly.in/question/6843974