Question

The difference between two positive numbers is 4 and the difference between
their cubes is 124. Find the sum of their squares.

Answer 1

Answer:

x-y=5,xy=24

x=5+y

put in xy=24

(5+y)y=24

5y+y square =24

y square+5y-24=0

by factorisation method

y=3,-8

we will take y=3 ,then x-5+33D8 so sum of these no.'s is 8+3=11, difference of their cube is 485,

sum of their cube is 539