Question

The difference between two positive numbers is 40 and the ratio of these
integers is 1:3. Find the integers.​

Answer 1

Step-by-step explanation:

Here

Let the two integers be x and y ( where x > y)

Then

Applying first condition, we get

x - y = 40

and

Applying second condition we get,

x. = 1

y. 3

Here

In first condition

x - y = 40

=> x = 40+y

Now, putting x = 40+y in second condition, we get -

40+y/ y = 1/3

=> (40+y)3= y

=> 120+3y = y

=> 3y-y = -120

=> 2y = -120

=>y = -120/2

=> y = -60

Then

x = 40+y = 40+(-60)= -20

So

the two integers are -20 and -60

hope it helps ✌

Answer 2

Answer:

The integers are 60 and 20.

Step-by-step explanation:

Let two numbers are x and y .

According to question ,

y - x = 40...... (i)

x/y = 1/3.

or , y = 3x..... (ii)

Put the value of y from equation (ii) on the equation (i).

3x-x=40.

or , 2x=40.

or , x = 20.

So , y = 3*x

or , y = 3 * 20.

or , y =  60.

The integers are 60 and 20.

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