Question

The difference between two positive numbers is 5 and the square of their sum is 169. Find the two numbers.​

Answer 1

Here Is your answer

x-y=5
x=5+y-----> 1

${x}^{2} + {y}^{2} = 169$
$(2y + 5) {}^{2} = \frac{ + }{ - } \sqrt{169}$
$2y + 5 = \frac{ + }{ - } 13$
$2y = - 5 + 13$
$\frac{2y}{2} = \frac{8}{2}$
$y = 4$
$2y = - 5 - 13$
$\frac{2y}{2} = \frac{ - 18}{2}$
$y = - 9$Ignore Negative sign

Y=4

Answer 2

Answer:9&5

Step-by-step explanation:

Let the first number be x

And other number be y.

From given first condition

x - y = 5 ..............(1)

From 2nd condition

(X+Y)2=169

Taking square root on both sides.

x+y =13.................(2)

Addind eqn 1 &2

x-y =5

+ x+y=13

--------------

2x. =18

:. x= 18/2

:. x=9

Put x=9 in eq 2 ; we get

:. 9+y=13

:. y=13-9

:. y = 4

:. THE TWO NUMBERS ARE 9 and 4.