Math, asked by Innu5927, 1 year ago

The difference betwwen the ages of two cousins is 10 years.15 yeras ago,if the elders one was twice as old as the younger one,find their present age.

Answers

Answered by sheikhyousupalpcbau4
0
let their present age x and y

now,according to the qsn ...
x-y=10 eqsn no (1)
15 years ago their age was x-15 and y-15
x-15=2(y-15)
=>x-15=2y-30
=>x=2y-15. eqsn no (2)

since eqsn no (1)=>10+y=2y-15
=>y=2y-25
=>-y=-25
=>y=25
so, x=10+y
=35
their present age is 35 and 25.
plz give me brainlist marks
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