Question

The difference betwwen the ages of two cousins is 10 years.15 yeras ago,if the elders one was twice as old as the younger one,find their present age.

Answer 1

let their present age x and y

now,according to the qsn ...
x-y=10 eqsn no (1)
15 years ago their age was x-15 and y-15
x-15=2(y-15)
=>x-15=2y-30
=>x=2y-15. eqsn no (2)

since eqsn no (1)=>10+y=2y-15
=>y=2y-25
=>-y=-25
=>y=25
so, x=10+y
=35
their present age is 35 and 25.
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