The difference in simple interest and compound interest on a certain sum of money in 2 years at 10% p.a. is ₹ 50. Find the sum.
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Answer:
Let the value of the sum be P.
First let us calculate simple interest obtained in the period of 2 years at rate of 10% per year,
S.I
= 100
P⋅R⋅T
= 100
P⋅10⋅2
= 5P
=0.2P
Now we will calculate the compound interest gained in the period of 2 years compounded annually at the rate of 10%,
C.I=A−P
=P(1+r) t
−P
=P((1+0.1)
2
−1)
=P((1.1)
2
−1
2
)
=P(1.1+1)(1.1−1)
=P(2.1)(0.1)
=0.21P
Now it is given that the difference between C.I and S.I is equal to Rs. 50. So,
C.I−S.I
0.21P−0.2P
0.01P
P
=50
=50
=50
=Rs. 5000
So, the sum is equal to Rs. 5000.
Step-by-step explanation:
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