The difference in the effective capacity of two similar capacitors when joined in series and then in parallel is 6 microfarad the capacity of each capacitor is
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effective capacitance of similar capacitors when joined in series = c÷n
= c÷2
effective capacitance of similar capacitors when connected in parallel = nc
= 2c
given c÷2-2c=6 microfarad
-3c= 12
c= 4 microfarad
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Answer:
4 μF
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