Question

The difference in the wavelength of the 1 line of Lyman series and 2 line of Balmer series in a hydrogen atom is​

Answer 1

Answer:

Explanation:

The first line of lyman series is

n1=1, n2=2

Therefore, 1/lambda =(1) ^2×(1/n1-1/n2) ^2

Ans.... Lamda1=4/3.

Whereas lamba 2=64/5

Lambda1/Lambda2=4/3×5/64=5/48.