The difference of 13% per annum and 12% of a sum in 3 yr is ₹110 . Then , the sum is
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6
Answer:
Let the sum be 'y'
then, [(y x13 x 1)/100 ]- [( y x 12 x 1) / 100]=110
since ( y / 100 ) = Rs 110
∴ Y = Rs 11000
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Answered by
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Answer:
let the sum be y
then [(y×13×1)/100]-[(y×12×1)/100]=110
y/100=110=11000
Explanation:
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