Question

The difference of 30th term and 10th term of the A.P 4 , 9 , 14 , 19 is

Answer 1

Step-by-step explanation:

Atq

a+29d-(a+9d)=?

a=4

d=5

Putting the values

4+145-4-45=100

Answer 2

$\huge\mathfrak\blue{Answer:}$

Given:

• We have been given an AP shown below
• AP = 4 , 9 , 14 , 19 ...

To Find:

• We have to find the difference of 30th term and 10th term

Concept used:

Arithmetic Progression are the series of numbers which increase or decrease at constant amount over time

For Eg : 2 , 4 , 6 , 8 ...

General term of an AP

$\large\boxed{\sf{\red{General \: Term = A + ( n - 1 ) \: D}}}$

Solution:

We have been given an AP such that

4 , 9 , 14 , 19 ....

________________________________

On observing the given Arithmetic Progression

$\boxed{\sf{First \: Term(a) = 4}}$

$\boxed{\sf{Common \: Difference(d) = 5}}$

________________________________

$\underline{\large\mathfrak\purple{Difference \: is \: as \: Follows:}}$

$\implies \sf{A_{30} - A_{10}}$

$\implies \sf{(a+29d) - (a+9d)}$

$\implies \sf{a + 29d - a - 9d}$

$\implies \sf{20d}$

Putting d = 5 in above equation

$\implies \sf{20 \times 5}$

$\implies \sf{100}$

Hence the Difference between 30th and 10th of AP is 100

________________________________

$\huge\underline{\sf{\red{A}\orange{n}\green{s}\pink{w}\blue{e}\purple{r}}}$

$\large\boxed{\sf{\red{Required \: Difference = 100}}}$

________________________________