Question

The difference of ages between two sisters is 10 years. 15 years ago if the elder one was twice as old as the younger one find their present ages.​

Answer 1

Answer:

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Answer 2

Present age of elder sister = 25 years

Present age of younger sister = 20 years

Step-by-step explanation:

Let the age of elder sister be x

Let the age of younger sister y

According to question

Difference of age between two sisters is 10 years

$x-y=5\\x=y+5-(i)$

15 years ago,if the elder one was twice as old as younger one.

$(x-15)=(2(y-15)\\x-15=2y-30\\x-2y=-30+15\\x-2y=-15-(ii)$

Put the value of x in equation (ii)

$y+5-2y=-15\\\-y=-15-5\\-y=-20\\y=20$

so,

the present age of elder sister = 25 years

the present age of younger sister = 20 years