The difference of CI SI for Rs 100000 at 10% pa for 3 years is
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Answer:
Principal sum = ₹1000, interest rate = 10%p.a. , time= 4yrs. Simple interest= P.R.T/100 = 1000×10×4/100 = 400. Compound interest= P{1+ R/100}™ - P =1000{1+10/1000}^4-1000 = 1464.1 - 1000 = 464.1 Thus difference in interests= 464.1 - 400 = ₹64.1.
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Answer:
If the difference between compound and simple interest is of two years then,
Difference = P(R)²/(100)²
Step-by-step explanation:
Here, P = 1,00,000
R = 10%
Then,
Difference = 1,00,000 * (10)^2 / (100)^2
Difference = 10,00.
10,000 is your answer.
Sorry if I made any mistake.
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