Question

The difference of cube and square of a real number is equal to the difference of its square and itself.
Total number of such real numbers are

Answer 1

Answer:

Step-by-step explanation:

$a^{3} - a^{2} = a^{2} - a\\ a^{3} - a^{2} - a^{2} + a = 0\\a(a^{2} - 2a +1) = 0\\ a = 0 or a^{2} -2a+1 = 0\\(a-1)(a-1) = 0$

therefore, a = 0,1,1

total number of such real numbers are 1