The difference of square of two natural numbers is 84. The square of the large number is 25 time smaller number. Find the number.
Using one variable only
Answers
Answered by
1
Let the smaller number be x
Larger number be y
The square of larger number, y^2 = 25x
According to the question,
y^2- x^2 = 84
25x - x^2 = 84
x^2 - 25x + 84 =0
x^2 - 21x- 4x +84 = 0
x (x-21) - 4 (x-21) = 0
(x-21) (x-4) = 0
The value of x is 21 or 4
Smaller number = 21 or 4
Larger number = 25×21 = 525
= 25 × 4 = 100
Hope it will help you
Larger number be y
The square of larger number, y^2 = 25x
According to the question,
y^2- x^2 = 84
25x - x^2 = 84
x^2 - 25x + 84 =0
x^2 - 21x- 4x +84 = 0
x (x-21) - 4 (x-21) = 0
(x-21) (x-4) = 0
The value of x is 21 or 4
Smaller number = 21 or 4
Larger number = 25×21 = 525
= 25 × 4 = 100
Hope it will help you
Similar questions