Question

the difference of square of two number is 88 if the larger number is 5 less than twice the smaller number then find the two numbers

Answer 1

let no. be x and y

x^2--y^2   =   88  [i]

x = 2y--5  [ii]

put value of x in eq. i

[2y--5]^2--y^2   = 88

4y^2 +25--12y =88

4y^2--63--12y  = 0

solve it u get your answer

Answer 2

Step-by-step explanation:

Let the numbers be x(larger) and y(smaller)

GT-

x^2-y^2=88

x=2y-5

applying

a ^{2} - b ^{2} = (a + b)(a - b)a

2

−b

2

=(a+b)(a−b)

we get

x^2-y^2=(x+y)(x-y)

substituting x=2y-5 in the above equation we get

(2y-5+y)(2y-5-y)=88

(3y-5)(y-5)=88

3y^2-15y-5y+25=88

3y^2-20y-63=0

3y^2-27y+7y-63=0

3y(y-9)+7(y-9)=0

(y-9)(3y+7)=0

y=9;y=-7/3

The numbers when

y=9;x=13

y=-7/3;x=-29/3

HOPE THIS HELPS.........