Question

the difference of squares of two no is 80 and the sum of the number is 20 then the largest number is​

Answer 1

Answer:

the largest number is 12.

Step-by-step explanation:

let the 2 numbers be x and y

A.T.Q,

x^2 - y^2 = 80.....(1) and,

x+y = 20

=> x= 20-y....(2)

substituting the value of x from equation (2) in equation(1)

(20-y)^2 - y^2 = 80

=> 400 - 40y + y^2 -y^2 = 80

=> -40y = 80-400

=> -40y = -320

=> 40y = 320

=> y= 320/40 = 8

so, x = 20-y (from equation 1)

x= 20-8 = 12

so the values of 2 numbers x and y are 12 and 8 respectively.

hope it will help you

Answer 2

Let first number be x and another number be y. Now x+y=80 and x-y=20. So the answer is 1600.

Step-by-step explanation:

Let first number be x and another number be y.

Now x+y=80 and x-y=20.

We can adjust second equation as x=20+y and put this value in equation one. Then we get

20+y+y=80

2y=80–20

y=30 and therefore x=50

Now the question is difference between squares of these numbers and the difference is

50^2-30^2=2500–900=1600

So the answer is 1600.

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