Question

the difference of squares of two numbers is 45 and square of smaller number is 4 times the larger number. Find the two number.​

Answer 1

Answer:

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Step-by-step explanation: Let two no/s be x(greater) and y(smaller)

Then acc to ques,

  x² - y² = 45  �       ...(1)

Also, 

        y² = 4x          ...(2)

From 1 and 2

Substituting 2 in 1

We get, 

    x² - y² = 45

    x² - 4x = 45

⇒ x² - 4x - 45

⇒ x² - 9x + 5x  -45

⇒ x(x - 9) + 5(x - 9)

⇒ (x+5)(x-9)

⇒ Then x = -5,9

If x = -5

  y² = 4(-5)

  y² = -20

  y  =  √-20       which is not applicable here

Negative neglected  

If x = 9

  y² = 4(9)

  y² = 36

   y = √36

   y = 6