Question

The difference of the ages two brothers is 6 years. Ifafa two years the
product of their ages will be 230, find the present age​

Answer 1

Answer:

Let present ages of two brothers are x & x+6.

After 2 years, their ages becomes x+2 & x+8.

A/Q (x+2)×(x+8) = 230

${x}^{2} + 10x + 16 = 230$

${x}^{2} + 10x - 214 = 0$

$x = \frac{ - 10 + \sqrt{ {10}^{2} + 4 \times 214 } }{2} = \frac{ - 10 + \sqrt{956} }{2}$

Ans.

Answer 2

Answer:

answer it not coming in integer. values should be different in question