The difference of the areas of a sector of angle 60⁰ and it's corresponding major sector of a circle of radius 21 cm is _______ sq.cm. (Use π=22/7)
1 point
900
865
942
924
Answers
Answered by
1
area of minor sector = theta / 360 × π r ²
= 60 / 360 × 22/7 × 21 × 21
= 231 cm²
area of major sector = 300 / 360 ×22 /7 ×21 ×21
= 1155cm²
difference = 1155 - 231
= 924
hope it helps you.........
Similar questions