Question

The difference of the areas of a sector of angle 60⁰ and it's corresponding major sector of a circle of radius 21 cm is _______ sq.cm. (Use π=22/7)
1 point
900
865
942
924​

Answer 1

area of minor sector = theta / 360 × π r ²

= 60 / 360 × 22/7 × 21 × 21

= 231 cm²

area of major sector = 300 / 360 ×22 /7 ×21 ×21

= 1155cm²

difference = 1155 - 231

= 924

hope it helps you.........