The difference of the car of a faster car and a slower car is a 20 km per hour is the slower car takes 1 hour more than the faster car to travel a distance of 400 km find speed of both the cars
Answers
Step-by-step explanation:
Let the speed of the slower car be x
Let the faster car be x+20
Distance=400km
Time taken by slower car - time taken by faster car= 1 hour
400/x - 400/x+20= 1
(x+20) 400 - 400x/ x( x+20 )= 1
400x + 8000 - 400x = x sq. + 20x
x sq. + 20x = 8000
x sq. + 20x - 8000 = 0
x sq. + 100x - 80x - 8000= 0
x(x + 100) - 80 (x + 100)= 0
(x - 80) (x + 100)= 0
x - 80 = 0
x = 0 + 80
therefore, x = 80 and x + 100=0
x=0-100
therefore x = -100 not possible
Hence,the speed of slower car is 80 km/hr
and the speed of faster car is 100 km/hr
Answer:
The Speed of faster car is 40 km/h
The Speed of slower car is 20 km/h
Step-by-step explanation:
Given as :
The total distance = d = 400 km
Let The speed of faster car = S km/h
The speed of slower car = s km/h
And The difference between the speed of car = (S - s) km/h = 20 km/h
The time taken by faster car = t hours
The slower car take one hour more than faster car
So, The time taken by slower car =( t + 1 ) hour
According to question
Distance = speed × time
For faster car
d = S × t
Or, 400 = S t
i.e t = .......1
For slower car
time =
Since time taken by slower car is 1 hour more
So, t + 1 =
Or, + 1 =
Or, - = 1
Or, 400 S - 400 (S - 20) = S (S - 20)
Or, 400 S - 400 S + 8000 = S² - 20 S
Or, 0 + 8000 = S² - 20 S
Or, S² - 20 S - 8000 = 0
Solving the equation
i.e S² - 40 S + 20 S - 8000 = 0
Or, S (S - 40 ) + 20 (S - 40) = 0
i.e (S - 40 ) ( S + 20) = 0
∴ S = 40 km/h , S = - 20
So, The Speed of faster car = S = 40 km/h
And The Speed of slower car = S - 20 = 40 - 20 = 20 km/h
Hence, The Speed of faster car is 40 km/h
And The Speed of slower car is 20 km/h Answer