Question

The difference of the present ages of sister and her younger brother is 6 years. the product of ages of numerical value is equal to 6 times the sum of their ages. find the present ages

Answer 1

Step-by-step explanation:

Let age of sister be x and brother be y.

so,

x-y = 6

xy = 6(x-y)

xy= 6*6

x= 36/y

then,

36/y-y =6

36-y2=6y

y2-6y+36=0

y2-12y+6y+36=0

(y-12) (y+6)=0

:y=12 and x=18 ans