Question

the difference of the sqaure of two no. is 80. and sum of no. 20 . then largest no. is
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Answer 1

Answer: The product of the two numbers is 22.

Step-by-step explanation:

Let the numbers are x and y,

Since, the sum of squares of two numbers is 80,

⇒ x² + y² = 80 -----(1)

And, the square of difference between the two numbers is 36,

⇒ (x - y)² = 36

⇒ x² + y² - 2 xy = 36

⇒ 80 - 2xy = 36 ( From equation (1) ),

⇒ -2xy = -44

⇒ xy = 22

Thus, the product of the two numbers is 22.

Answer 2

Answer:

Step-by-step explanation:

Let the numbers are x and y,

Since, the sum of squares of two numbers is 80,

⇒ x² + y² = 80 -----(1)

And, the square of difference between the two numbers is 36,

⇒ (x - y)² =20

⇒ x² + y² - 2 xy = 20

⇒ 80 - 2xy = 20 ( From equation (1) ),

⇒ -2xy = -60

⇒ xy = 30

Thus, the product of the two numbers is 30.