The difference of the square of two consecutive integers a and b (b>a) is 25. Find a and b.
Answers
Answered by
0
b=13 and a=12
b^2-a^2= 169-144=25
b^2-a^2= 169-144=25
Answered by
2
let a = x
b= x+1
(x+1)^{2} -x^2 = 25
x^2 + 2x + 1 -x^2=25
2x= 24
x =12
therefore a=12,b=13
b= x+1
(x+1)^{2} -x^2 = 25
x^2 + 2x + 1 -x^2=25
2x= 24
x =12
therefore a=12,b=13
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