Question

the difference of the squares of 2 consecutive integers is divisible by what​

Answer 1

Answer:

Let the two consecutive even integers be 2n and (2n+2). Then,

Let the two consecutive even integers be 2n and (2n+2). Then,(2n+2)

Let the two consecutive even integers be 2n and (2n+2). Then,(2n+2) 2

Let the two consecutive even integers be 2n and (2n+2). Then,(2n+2) 2 =(2n+2+2n)(2n+2−2n)

Let the two consecutive even integers be 2n and (2n+2). Then,(2n+2) 2 =(2n+2+2n)(2n+2−2n) =2(4n+2)

Let the two consecutive even integers be 2n and (2n+2). Then,(2n+2) 2 =(2n+2+2n)(2n+2−2n) =2(4n+2) =4(2n+1), which is divisible by 4.

Answer 2

Answer:

ANSWER

Let the two consecutive even integers be 2n and (2n+2). Then,

(2n+2)

2

=(2n+2+2n)(2n+2−2n)

=2(4n+2)

=4(2n+1), which is divisible by 4.