Question

the difference of the tens and ones digit of a two digit number is 3.the number is sixteen times the digit in ones place.find the number​

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

$Let \: the \: ten's \: place \:digit = x$

$Unit \:place \:digit = (x-3)$

/*The difference of the tens and ones digit of a two digit number is 3 */

$\blue { The \: number }\\= 10x + (x-3)\\= 10x + x - 3 \\= 11x - 3 \: ---(1)$

/* According to the problem given */

$The \: number = 16 \times ( One's \:place \:digit )$

$\implies 11x-3 = 16(x-3)$

$\implies 11x - 3 = 16x - 48$

$\implies 11x - 16x = -48 + 3$

$\implies - 5x = -45$

$\implies x = \frac{-45}{-5}$

$\implies x = 9$

/* put x = 9 in equation (1), we get */

$\blue { The \: number }\\= 11\times 9 - 3 \\= 99 - 3 \\= 96$

Therefore.,

$\red{ Required \: number } \green {= 96}$

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